Erdős–Szekeres 1935 upper bound for the diagonal Ramsey number #
Statement (Erdős–Szekeres 1935): For every k : ℕ, the diagonal Ramsey number satisfies
Combinatorics.hypergraphRamsey 2 k ≤ 4 ^ k.
Proof sketch. Use the symmetric recursion R(s, t) ≤ R(s-1, t) + R(s, t-1) with base
cases R(0, t) = R(s, 0) = 1. Induction on s + t then gives R(s, t) ≤ C(s+t, s); for
s = t = k this is R(k, k) ≤ C(2k, k) ≤ 4 ^ k (the Catalan-like central binomial
coefficient bound).
The whole argument is phrased directly on the Mathlib-style coloring data
c : Finset (Fin m) → Bool of 2-element subsets — no auxiliary "edge colouring" structure
is introduced.
Reference: [ES35] Erdős, P. and Szekeres, G. (1935). "A combinatorial problem in geometry." Compositio Math. 2, pp. 463–470.
Central binomial bound (Mathlib wrapper). C(2n, n) ≤ 4 ^ n.
This specialises Nat.choose_middle_le_pow : (2n+1).choose n ≤ 4^n by observing that
(2n).choose n ≤ (2n+1).choose n via the monotonicity lemma Nat.choose_le_succ.
Off-diagonal Ramsey via a subset-indexed predicate #
Rather than introduce an auxiliary edge-colouring structure, we phrase the off-diagonal
Ramsey statement as a property of an arbitrary Finset (Fin m) of sufficient cardinality
inside a Bool-valued coloring of all subsets of Fin m. We only ever query the coloring
on 2-element subsets. This setup matches the shape of
Combinatorics.hypergraphRamsey 2 directly.
HasRamseyProperty N s t asserts: for every m, every coloring
c : Finset (Fin m) → Bool, and every V : Finset (Fin m) with V.card ≥ N, the subset
V contains either a subset of size s whose 2-element subsets are all false-coloured,
or a subset of size t whose 2-element subsets are all true-coloured.
This is the "off-diagonal Ramsey number does not exceed N" form of the classical
Erdős–Szekeres Ramsey recurrence, packaged in the same shape used by
Combinatorics.hypergraphRamsey.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Monotonicity. If N ≤ N' then HasRamseyProperty N s t → HasRamseyProperty N' s t.
Base case s = 0. Any V contains an empty false-monochromatic set.
Base case t = 0. Any V contains an empty true-monochromatic set.
Base case s = 1. Any nonempty V contains a singleton false-monochromatic set.
Base case t = 1. Any nonempty V contains a singleton true-monochromatic set.
Pigeonhole step: splitting V \ {v} by colour. For any vertex v ∈ V, the set
V.erase v partitions into false-neighbours of v and true-neighbours of v, and the
cardinalities sum to V.card - 1.
Recurrence. If HasRamseyProperty Ns s (t+1) and HasRamseyProperty Nt (s+1) t
hold, then HasRamseyProperty (Ns + Nt) (s+1) (t+1) holds.
This is the core Erdős–Szekeres 1935 pigeonhole step: pick any vertex v ∈ V, split
V.erase v into false-neighbours R_v and true-neighbours B_v; by pigeonhole
|R_v| ≥ Ns or |B_v| ≥ Nt. In the first case, invoke HasRamseyProperty Ns s (t+1)
on R_v: either we get a false-mono K_s on R_v (extend by v to a false-mono
K_{s+1} on V), or a true-mono K_{t+1} on R_v ⊆ V (done). The second case is
symmetric.
Binomial bound via Erdős–Szekeres induction.
HasRamseyProperty (Nat.choose (s + t) s) s t for all s, t.
Erdős–Szekeres 1935 in hypergraphRamsey form:
Combinatorics.hypergraphRamsey 2 k ≤ 4 ^ k for all k.
Proof. Diagonal.hasRamseyProperty_choose applied at s = t = k and the full vertex
set V = Finset.univ of Fin (C(2k, k)) shows that C(2k, k) is a member of the defining
set of hypergraphRamsey 2 k, hence by Nat.sInf_le we get
hypergraphRamsey 2 k ≤ C(2k, k); the central binomial bound
C(2k, k) ≤ 4 ^ k closes the result.