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FormalConjectures.Paper.ZagierMZV

Zagier's Conjecture on Multiple Zeta Values #

References:

noncomputable def ZagierMZV.multiZeta :

The multiple zeta value $\zeta(s_1, s_2, \ldots, s_k)$, defined as $$\zeta(s_1, \ldots, s_k) = \sum_{n_1 > n_2 > \cdots > n_k > 0} \frac{1}{n_1^{s_1} n_2^{s_2} \cdots n_k^{s_k}}.$$ The argument is a list of positive natural numbers. The value is well-defined (i.e. the series converges) when the first entry is at least 2, but we define it for all inputs. For the empty list, multiZeta [] = 1 (the empty product convention).

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    noncomputable def ZagierMZV.multiZeta.aux :
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    Auxiliary function for multiZeta: computes the inner sum $\sum_{n_2 > \cdots > n_k > 0, n_2 < \text{bound}} \frac{1}{n_2^{s_2} \cdots n_k^{s_k}}$.

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      The weight of an MZV index $(s_1, \ldots, s_k)$ is $s_1 + \cdots + s_k$.

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        An MZV index is admissible if it is either empty or if the first entry is at least 2 and all entries are positive. The empty list convention ensures $\mathcal{Z}_0 = \mathbb{Q}$.

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          The set of all MZV values of weight $n$.

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            noncomputable def ZagierMZV.mzvSpanOfWeight (n : ) :

            The $\mathbb{Q}$-submodule of $\mathbb{R}$ spanned by all MZVs of weight $n$.

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              The conjectured Zagier dimension sequence $d_n$, defined by $d_0 = 1$, $d_1 = 0$, $d_2 = 1$, and $d_n = d_{n-2} + d_{n-3}$ for $n \geq 3$.

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                Zagier's conjecture

                The $\mathbb{Q}$-dimension of the vector space spanned by all multiple zeta values of weight $n$ equals $d_n$, where $d_n$ is the Zagier dimension sequence satisfying $d_0 = 1$, $d_1 = 0$, $d_2 = 1$, and $d_n = d_{n-2} + d_{n-3}$ for $n \geq 3$.

                Upper bound [Te02, DG05]

                The dimension of the $\mathbb{Q}$-vector space of MZVs of weight $n$ is at most $d_n$.

                The first few values of $d_n$ are $1, 0, 1, 1, 1, 2, 2, 3, 4, 5, 7, 9, \ldots$

                There is no admissible index of weight 1 (since $s_1 \geq 2$ is required).

                $\mathcal{Z}_0 = \mathbb{Q}$, so $\dim_\mathbb{Q}(\mathcal{Z}_0) = 1$.

                $\mathcal{Z}_1 = \emptyset$, so $\dim_\mathbb{Q}(\mathcal{Z}_1) = 0$.

                Euler's identity: $\zeta(2) = \pi^2/6$.

                Euler's identity for $\zeta(4) = \pi^4/90$.