Ben Green's Open Problem 31 #
Write $F(N)$ for the largest Sidon subset of $[N]$. Improve, at least for infinitely many $N$, the bounds $N^{1/2} + O(1) \le F(N) \le N^{1/2} + N^{1/4} + O(1)$.
Note: the upper bound was improved to $N^{1/2} + 0.98183 N^{1/4} + O(1)$ in [CHO25].
Related to Erdős Problem 30.
References:
- [Gr24] [Ben Green's Open Problem 31](https://people.maths.ox.ac.uk/greenbj/papers/open-problems.pdf#section.7 Problem 31)
- [Gr01] Green, Ben. "The number of squares and $ B_h [g] $ sets." Acta Arithmetica 100.4 (2001): 365-390.
- [BFR23] Balogh, József, Zoltán Füredi, and Souktik Roy. "An upper bound on the size of Sidon sets." The American Mathematical Monthly 130.5 (2023): 437-445.
- [CHO25] Carter, Daniel, Zach Hunter, and Kevin O’Bryant. "On the diameter of finite Sidon sets." Acta Mathematica Hungarica 175.1 (2025): 108-126.
- [ET41] Erdos, Paul, and Pál Turán. "On a problem of Sidon in additive number theory, and on some related problems." J. London Math. Soc 16.4 (1941): 212-215.
- [Li69] Lindström, Bernt. “A remark on B4-Sequences.” Journal of Combinatorial Theory, Series A 7 (1969): 276-277.
- [CLZ01] Cohen, G.D., Litsyn, S., & Zémor, G. (2001). Binary B2-Sequences : A New Upper Bound. J. Comb. Theory A, 94, 152-155.
Let $F(N)$ be the largest Sidon subset of $[N]$.
Equations
- Green31.F N = ↑(Finset.Icc 1 N).maxSidonSubsetCard
Instances For
Can we improve the lower bound $N^{1/2} + O(1)$, at least for infinitely many $N$?
Can we improve the lower bound $N^{1/2} + O(1)$, for all sufficiently large $N$?
Can we improve the upper bound $N^{1/2} + 0.98183 N^{1/4} + O(1)$ [CHO25], for all sufficiently large $N$?
It is not known whether or not there exists a Sidon subset of $\mathbb{Z}/p\mathbb{Z}$ of size $(1 + o(1))\sqrt{p}$, for all $p$ [Gr24].
It is not known whether, if $G$ is an abelian group of size $n$, there always exists a Sidon subset of $G$ of size $0.01\sqrt{n}$ [Gr24].
Another very nice old problem is whether there is a Sidon subset of $\{0, 1\}^n$ of size $N^{0.51}$, where $N = 2^n$ [Gr24].