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FormalConjectures.ErdosProblems.«978»

Erdős Problem 978 #

Reference:

theorem Erdos978.erdos_978.variants.sub_one {f : Polynomial } (hi : Irreducible f) (hd : 2 < f.natDegree) (hp : ∀ (x : ), f.natDegree 2 ^ x) (hlc : 0 < f.leadingCoeff) :

Let f ∈ ℤ[X] be an irreducible polynomial with positive leading coefficient. Suppose that the degree k of f is larger than 2 and is not equal to a power of 2. Then the set of n such that f n is (k - 1)-th power free is infinite, and this is proved in [Er53].

theorem Erdos978.erdos_978.parts.i {f : Polynomial } (hi : Irreducible f) (hd : 2 < f.natDegree) (hp2 : ∀ (x : ), f.natDegree 2 ^ x) (hlc : 0 < f.leadingCoeff) (hp : ∀ (p : ), Nat.Prime p∃ (n : ), ¬p ^ (f.natDegree - 1) Polynomial.eval (↑n) f) :

Let f ∈ ℤ[X] be an irreducible polynomial with positive leading coefficient. Suppose that the degree k of f is larger than 2, is not equal to a power of 2, and f n has no fixed (k - 1)-th power divisors other than 1. Then the set of n such that f n is (k - 1)-th power free has positive density, and this is proved in [Ho67].

theorem Erdos978.erdos_978.variants.sub_two {f : Polynomial } (hi : Irreducible f) (hd : 9 f.natDegree) (hp : ∀ (p : ), Nat.Prime p∃ (n : ), ¬p ^ (f.natDegree - 1) Polynomial.eval (↑n) f) :

If the degree k of f is larger than or equal to 9, then the set of n such that f n is (k - 2)-th power free has infinitely many elements. This result is proved in [Br11].

theorem Erdos978.erdos_978.parts.ii :
True ∀ {f : Polynomial }, Irreducible ff.natDegree > 3(¬∃ (l : ), f.natDegree = 2 ^ l) → 0 < f.leadingCoeff(¬∃ (p : ), Nat.Prime p ∀ (n : ), p ^ (f.natDegree - 1) Polynomial.eval (↑n) f) → {n : | Powerfree (f.natDegree - 2) (Polynomial.eval (↑n) f)}.Infinite

If $k > 3$ (and $k \neq 2^l$), then are there infinitely many $n$ for which $f(n)$ is $(k-2)$-power-free?

Does n ^ 4 + 2 represent infinitely many squarefree numbers?