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FormalConjectures.ErdosProblems.«950»

Erdős Problem 950 #

References:

noncomputable def Erdos950.f (n : ) :

Let $f(n) = \sum_{p<n}\frac{1}{n-p}$.

Equations
Instances For
    theorem Erdos950.erdos_950.parts.i :
    sorry Filter.liminf (fun (n : ) => (f n)) Filter.atTop = 1

    Is it true that $\liminf f(n)=1$?

    theorem Erdos950.erdos_950.parts.ii :
    sorry Filter.limsup (fun (n : ) => (f n)) Filter.atTop =

    Is it true that $\limsup f(n)=\infty$?

    Is it true that $f(n)=o(\log\log n)$ for all $n$?

    theorem Erdos950.erdos_950.variants.debruijn_erdos_turan :
    (Asymptotics.IsEquivalent Filter.atTop (fun (x : ) => nFinset.range x, f n) fun (x : ) => x) Asymptotics.IsEquivalent Filter.atTop (fun (x : ) => nFinset.range x, f n ^ 2) fun (x : ) => x

    This function was considered by de Bruijn, Erdős, and Turán, who showed that $\sum_{n<x}f(n)\sim \sum_{n<x}f(n)^2\sim x$. They gave no proofs, but a proof of the (harder) second claim is given by Gorodetsky here [mathoverflow/508491].

    theorem Erdos950.erdos_950.variants.weaker_pi :
    sorry ε > 0, ∀ᶠ (x : ) in Filter.atTop, y < x, x.primeCounting < y.primeCounting + ε * (x - y).primeCounting

    Erdős writes that a 'weaker conjecture which is perhaps not quite inaccessible' is that, for every $\epsilon>0$, if $x$ is sufficiently large there exists $y<x$ such that $\pi(x)< \pi(y)+\epsilon \pi(x-y)$. Compare this to [855].

    theorem Erdos950.erdos_950.variants.weaker_pi_implies_f (h : C > 0, K > 0, ∀ᶠ (x : ) in Filter.atTop, ∀ (y : ), y < x - Real.log x ^ Cx.primeCounting < y.primeCounting + K * ((x - y) / Real.log x)) :

    He notes that if $\pi(x)< \pi(y)+O\left(\frac{x-y}{\log x}\right)$ for all $y<x-(\log x)^C$ for some constant $C>0$ then $f(n)\ll \log\log\log n$.

    theorem Erdos950.erdos_950.variants.sum_primes :
    sorry Asymptotics.IsEquivalent Filter.atTop (fun (x : ) => pFinset.range x with Prime p, f p ^ 2) fun (x : ) => x.primeCounting

    The study of $f(p)$ is even harder, and Erdős could not prove that $\sum_{p<x}f(p)^2\sim \pi(x)$.