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Are there infinitely many pairs of integers $n < m$ such that $\binom{2n}{n}$ and $\binom{2m}{m}$ have the same set of prime divisors?
For example, $(87,88)$ and $(607,608)$ are such pairs.
There are examples where $(n, m) ∈ S$ with $m ≠ n + 1$.
(Found by AlphaProof, although it was implicit already in [A129515])