Erdős Problem 596 #
References:
- erdosproblems.com/596
- [Er87] Erdős, Some of my favourite problems in various branches of combinatorics, Mat. Lapok 1987.
- [NeRo75] Nešetřil and Rödl, The Ramsey property for graphs with forbidden complete subgraphs, J. Combin. Theory B 20 (1976), 243--249.
Erdős Problem 596 (Erdős–Hajnal, [Er87]). For which graph pairs $(G_1, G_2)$ is it true that
(1) for every $n \geq 1$ there is a graph $H$ without a $G_1$ such that any $n$-colouring of $H$'s edges contains a monochromatic $G_2$, and yet (2) for every graph $H$ without a $G_1$ there is an $\aleph_0$-colouring of $H$'s edges with no monochromatic $G_2$?
Erdős and Hajnal originally conjectured that no such pair exists; but $(C_4, C_6)$
witnesses it (Nešetřil–Rödl + Erdős–Hajnal). The full question is to characterise the
class of all such pairs, recorded here as answer(sorry).
See Problem 595 for the specific case $(G_1, G_2) = (K_4, K_3)$.
Erdős–Hajnal exceptional pairs exist — recorded as a known direction of erdos_596.
Every $C_4$-free graph is a countable union of trees (Erdős–Hajnal [Er87]); trees are acyclic, hence $C_6$-free, giving the countable Ramsey escape for $(C_4, C_6)$.
Nešetřil–Rödl [NeRo75]: for every $n \geq 1$ there is a $C_4$-free graph whose edges cannot be $n$-coloured without a monochromatic $C_6$.
The pair $(C_4, C_6)$ is Erdős–Hajnal exceptional; combines C4_C6_finite_ramsey and
C4_free_countable_escape.
The original Erdős–Hajnal conjecture (that no exceptional pair exists) is false —
witnessed by $(C_4, C_6)$ via C4_C6_is_exceptional.
Whether $(K_4, K_3)$ is Erdős–Hajnal exceptional is precisely the content of Erdős Problem 595. The finite Ramsey property holds (Folkman 1970, Nešetřil–Rödl [NeRo75]); the open part is whether every $K_4$-free graph is a countable union of triangle-free graphs.
Folkman 1970 / Nešetřil–Rödl [NeRo75]: for every $n \geq 1$ there is a $K_4$-free graph whose edges cannot be $n$-coloured without a monochromatic triangle.
The empty graph on Fin 0 is Free of any nontrivial subgraph (vacuous). This is the
simplest non-trivial witness to G₁.Free H appearing in HasFiniteRamseyProperty.