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FormalConjectures.ErdosProblems.«596»

Erdős Problem 596 #

References:

theorem Erdos596.erdos_596 {U₁ U₂ : Type} (G₁ : SimpleGraph U₁) (G₂ : SimpleGraph U₂) :
G₁.IsErdosHajnalExceptional G₂ (fun {U₁ U₂ : Type} => sorry) G₁ G₂

Erdős Problem 596 (Erdős–Hajnal, [Er87]). For which graph pairs $(G_1, G_2)$ is it true that

(1) for every $n \geq 1$ there is a graph $H$ without a $G_1$ such that any $n$-colouring of $H$'s edges contains a monochromatic $G_2$, and yet (2) for every graph $H$ without a $G_1$ there is an $\aleph_0$-colouring of $H$'s edges with no monochromatic $G_2$?

Erdős and Hajnal originally conjectured that no such pair exists; but $(C_4, C_6)$ witnesses it (Nešetřil–Rödl + Erdős–Hajnal). The full question is to characterise the class of all such pairs, recorded here as answer(sorry).

See Problem 595 for the specific case $(G_1, G_2) = (K_4, K_3)$.

theorem Erdos596.erdos_596.variants.exists_exceptional :
∃ (U₁ : Type) (U₂ : Type) (G₁ : SimpleGraph U₁) (G₂ : SimpleGraph U₂), G₁.IsErdosHajnalExceptional G₂

Erdős–Hajnal exceptional pairs exist — recorded as a known direction of erdos_596.

Every $C_4$-free graph is a countable union of trees (Erdős–Hajnal [Er87]); trees are acyclic, hence $C_6$-free, giving the countable Ramsey escape for $(C_4, C_6)$.

Nešetřil–Rödl [NeRo75]: for every $n \geq 1$ there is a $C_4$-free graph whose edges cannot be $n$-coloured without a monochromatic $C_6$.

The original Erdős–Hajnal conjecture (that no exceptional pair exists) is false — witnessed by $(C_4, C_6)$ via C4_C6_is_exceptional.

Whether $(K_4, K_3)$ is Erdős–Hajnal exceptional is precisely the content of Erdős Problem 595. The finite Ramsey property holds (Folkman 1970, Nešetřil–Rödl [NeRo75]); the open part is whether every $K_4$-free graph is a countable union of triangle-free graphs.

Folkman 1970 / Nešetřil–Rödl [NeRo75]: for every $n \geq 1$ there is a $K_4$-free graph whose edges cannot be $n$-coloured without a monochromatic triangle.

The empty graph on Fin 0 is Free of any nontrivial subgraph (vacuous). This is the simplest non-trivial witness to G₁.Free H appearing in HasFiniteRamseyProperty.