Documentation

FormalConjectures.ErdosProblems.«456»

Erdős Problem 456 #

References:

noncomputable def Erdos456.p (n : ) :

Let $p_n$ be the smallest prime $\equiv 1\pmod{n}$.

Equations
Instances For
    noncomputable def Erdos456.m (n : ) :

    Let $m_n$ be the smallest integer such that $n\mid \phi(m_n)$.

    Equations
    Instances For
      theorem Erdos456.erdos_456.parts.i :
      sorry Filter.Tendsto (fun (N : ) => (Nat.count {n : | m n < p n} N) / N) Filter.atTop (nhds 1)

      Is it true that $m_n<p_n$ for almost all $n$?

      theorem Erdos456.erdos_456.parts.ii :
      sorry ∃ (A : Set ), Filter.Tendsto (fun (N : ) => (Nat.count A N) / N) Filter.atTop (nhds 1) Filter.Tendsto (fun (n : ) => (p n) / (m n)) (Filter.atTopFilter.principal A) Filter.atTop

      Does $p_n/m_n \to \infty$ for almost all $n$?

      theorem Erdos456.erdos_456.parts.iii :
      sorry {q : | Nat.Prime q ∀ (n : ), m n = q n = q - 1}.Infinite

      Are there infinitely many primes $p$ such that $p-1$ is the only $n$ for which $m_n=p$?

      theorem Erdos456.erdos_456.variants.linniks_theorem :
      ∃ (L : ), (fun (n : ) => (p n)) =O[Filter.atTop] fun (n : ) => n ^ L

      Linnik's theorem implies that $p_n\leq n^{O(1)}$.

      It is trivial that $m_n \leq p_n$ always.

      Erdős [Er79e] writes it is 'easy to show' that for infinitely many $n$ we have $m_n < p_n$.

      theorem Erdos456.erdos_456.variants.m_div_n :
      ∃ (A : Set ), Filter.Tendsto (fun (N : ) => (Nat.count A N) / N) Filter.atTop (nhds 1) Filter.Tendsto (fun (n : ) => (m n) / n) (Filter.atTopFilter.principal A) Filter.atTop

      Erdős [Er79e] writes it is 'easy to show' that $m_n/n \to \infty$ for almost all $n$.