Erdős Problem 1167 #
Reference: erdosproblems.com/1167
The original Erdős–Hajnal problem list gives the additional conditions $\gamma \geq 2$, $r < \omega$,
and $\kappa_\alpha > r$. Without $\gamma \geq 2$, the statement is false: taking $\gamma = 1$ and
$\kappa_0 = \aleph_1$ with $\lambda = \aleph_0$ gives a counterexample, since the partition relation
with one color degenerates to a cardinality comparison (see erdos_1167.unrestricted_is_false).
Erdős Problem 1167. Let $r \geq 2$ be finite, $\gamma \geq 2$, and $\lambda$ be an infinite cardinal. Let $\kappa_\alpha$ be cardinals for all $\alpha < \gamma$. Is it true that $$2^\lambda \to (\kappa_\alpha + 1)_{\alpha < \gamma}^{r+1}$$ implies $$\lambda \to (\kappa_\alpha)_{\alpha < \gamma}^r?$$ Here $+$ means cardinal addition, so that $\kappa_\alpha + 1 = \kappa_\alpha$ if $\kappa_\alpha$ is infinite.
A problem of Erdős, Hajnal, and Rado.
Finite-target case. When all $\kappa_\alpha$ are finite, $\kappa_\alpha + 1$
is the ordinary natural-number successor. Special case of erdos_1167.
Binary-color case. The $\gamma = 2$ specialization (two color classes).
Infinite-target case. When all $\kappa_\alpha \geq \aleph_0$ are infinite and bounded by
$\lambda$, $\kappa_\alpha + 1 = \kappa_\alpha$, so the hypothesis simplifies to a "pure"
stepping-down lemma:
$$2^\lambda \to (\kappa_\alpha)_{\alpha<\gamma}^{r+1} \implies \lambda \to (\kappa_\alpha)_{\alpha<\gamma}^r.$$
The condition $\kappa_\alpha \leq \lambda$ is needed to avoid a size obstruction: without it, the
conclusion would require a subset of $\lambda$ of size $\kappa_\alpha > \lambda$, which is impossible
(see infinite_targets_needs_bound).
$r = 2$ case. The stepping-down from 3-uniform to 2-uniform partition relations: $2^\lambda \to (\kappa_\alpha + 1)_{\alpha<\gamma}^3$ implies $\lambda \to (\kappa_\alpha)_{\alpha<\gamma}^2$. Generalises the classical Erdős–Rado stepping-up/down theorem for pairs.
A canonical element of the type (1 : Ordinal).ToType.
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Instances For
The partition relation $\mu \to (\nu)^r_1$ with a single color is equivalent to $\nu \le \mu$.
The unrestricted version of Erdős Problem 1167 (without the condition $\gamma \geq 2$ from the original Erdős–Hajnal list) is false. Taking $\gamma = 1$, $\kappa_0 = \aleph_1$, $\lambda = \aleph_0$: the premise $2^{\aleph_0} \to (\aleph_1 + 1)^3_1$ holds since $2^{\aleph_0} \geq \aleph_1$, but the conclusion $\aleph_0 \to (\aleph_1)^2_1$ fails since $\aleph_0 < \aleph_1$.
The infinite_targets variant without the bound $\kappa_\alpha \leq \lambda$ is false.
Taking $\gamma = 1$, $\kappa_0 = 2^{\aleph_0}$, $\lambda = \aleph_0$: the premise
$2^{\aleph_0} \to (2^{\aleph_0})^3_1$ holds since $2^{\aleph_0} \leq 2^{\aleph_0}$, but the
conclusion $\aleph_0 \to (2^{\aleph_0})^2_1$ fails by Cantor's theorem.