Erdős Problem 1138 #
References:
- erdosproblems.com/1138
- [Va99] Vardi, I., Prime census. (1999).
- [Kum26] Kumrawat, S., Disproof of Erdős Problem 1138.
Note that the conjecture has a claimed disproof found at: https://sourish-kumrawat.github.io/papers/Erdos_1138.pdf, see the discussion section on the Erdos problems website for more information.
The maximal prime gap below $x$, i.e. $d(x) = \max_{p_n < x}(p_{n+1} - p_n)$, where $p_n$ denotes the $n$-th prime.
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The filter on $\mathbb{R} \times \mathbb{R}$ corresponding to sending $x \to \infty$ subject to $x/2 < y < x$
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- Erdos1138.snd_gt_half_fst = Filter.comap Prod.fst Filter.atTop ⊓ Filter.principal {p : ℝ × ℝ | p.2 ∈ Set.Ioo (p.1 / 2) p.1}
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Given a pair $(x,y)$, this is the amount of primes in the interval above $y$, of length equalling the largest prime gap before $x$, scaled by a constant $C$.
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- Erdos1138.primeCount_Ioc_mul_const C (x_1, y) = ↑⌊y + C * ↑(Erdos1138.sup_primeGap x_1)⌋₊.primeCounting - ↑⌊y⌋₊.primeCounting
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Erdős Problem 1138. Let $x/2 < y < x$ and $C > 1$. If $d = \max_{p_n < x}(p_{n+1} - p_n)$, where $p_n$ denotes the $n$-th prime, then is it true that $$\pi(y + Cd) - \pi(y) \sim \frac{Cd}{\log y}$$?