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FormalConjectures.ErdosProblems.«1128»

Erdős Problem 1128 #

Reference: erdosproblems.com/1128

def Erdos1128.IsMonochromaticBox {A : Type u_1} {B : Type u_2} {C : Type u_3} (f : ABCFin 2) (A₁ : Set A) (B₁ : Set B) (C₁ : Set C) :

A subset $A_1 \times B_1 \times C_1$ of $A \times B \times C$ is monochromatic under a 2-colouring $f : A \to B \to C \to \operatorname{Fin} 2$ if $f$ is constant on $A_1 \times B_1 \times C_1$.

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    theorem Erdos1128.erdos_1128.prikryMills :
    ∃ (X : Type) (_ : Cardinal.mk X = Cardinal.aleph 1) (f : XXXFin 2), ∀ (A₁ B₁ C₁ : Set X), Cardinal.mk A₁ = Cardinal.aleph 0Cardinal.mk B₁ = Cardinal.aleph 0Cardinal.mk C₁ = Cardinal.aleph 0¬IsMonochromaticBox f A₁ B₁ C₁

    Prikry–Mills counterexample (key lemma):

    There exists a 2-colouring $f$ of a set of cardinality $\aleph_1$ cubed such that no countable box $A_1 \times B_1 \times C_1$ is monochromatic.

    This is the unpublished result of Prikry and Mills (1978). The proof proceeds by transfinite induction along $\omega_1$, which has uncountable cofinality, ensuring every countable box is non-monochromatic.

    theorem Erdos1128.erdos_1128 :
    False ∀ (A B C : Type), Cardinal.mk A = Cardinal.aleph 1Cardinal.mk B = Cardinal.aleph 1Cardinal.mk C = Cardinal.aleph 1∀ (f : ABCFin 2), ∃ (A₁ : Set A) (B₁ : Set B) (C₁ : Set C), Cardinal.mk A₁ = Cardinal.aleph 0 Cardinal.mk B₁ = Cardinal.aleph 0 Cardinal.mk C₁ = Cardinal.aleph 0 IsMonochromaticBox f A₁ B₁ C₁

    Erdős Problem 1128 (disproved by Prikry–Mills, 1978):

    Erdős asked whether every 2-colouring of $A \times B \times C$, where $|A| = |B| = |C| = \aleph_1$, must contain a monochromatic countable box $A_1 \times B_1 \times C_1$ with $|A_1| = |B_1| = |C_1| = \aleph_0$.

    The answer is No: Prikry and Mills constructed a 2-colouring of $\omega_1^3$ with no monochromatic countable box.

    Note: The positive statement asserts that every 2-colouring of every $\aleph_1^3$ contains a monochromatic countably infinite box. Since the answer is False, this positive statement fails.

    Explicit form of Prikry–Mills:

    There exists a 2-colouring of $\omega_1 \times \omega_1 \times \omega_1$ such that for every countably infinite $A_1, B_1, C_1 \subseteq \omega_1$, the box $A_1 \times B_1 \times C_1$ is not monochromatic.

    This is the content of the Prikry–Mills theorem (1978, unpublished), stated using Lean's ordinal type {o : Ordinal // o < ω_ 1} as the representation of $\omega_1$.

    theorem Erdos1128.erdos_1128.variants.two_dimensional_false :
    ¬∀ (f : Erdos1128.Omega1✝Erdos1128.Omega1✝Fin 2), ∃ (A₁ : Set Erdos1128.Omega1✝¹) (B₁ : Set Erdos1128.Omega1✝²), ¬A₁.Countable ¬B₁.Countable ∃ (c : Fin 2), aA₁, bB₁, f a b = c

    The claim that every 2-colouring of $\omega_1 \times \omega_1$ has an uncountable monochromatic product rectangle is false in ZFC.

    Counterexample: The ordering colouring $f(\alpha, \beta) = 0$ iff $\alpha < \beta$ has no uncountable monochromatic product rectangle $A_1 \times B_1$.

    Proof: If $A_1 \times B_1$ were monochromatic with colour 0, then every element of $A_1$ would be strictly less than every element of $B_1$, making $A_1$ bounded above in $\omega_1$; but any bounded subset of $\omega_1$ is countable (since initial segments are countable), contradicting $A_1$ being uncountable. The colour-1 case is symmetric with the roles of $A_1$ and $B_1$ swapped.

    Note: The correct classical result for 2-colourings of pairs (not products) is the Erdős–Rado theorem $\omega_1 \to (\omega_1)^2_2$, which concerns unordered pairs.