A set S
in ℝⁿ
is called a Kakeya set if it contains a unit line segment in every direction.
For simplicity, we omit the compactness assumption here.
For a discussion on the equivalence of definitions with and without compactness, see
this paper.
Equations
- Kakeya.IsKakeya S = ∀ (v : EuclideanSpace ℝ (Fin n)), ‖v‖ = 1 → ∃ (a : EuclideanSpace ℝ (Fin n)), affineSegment ℝ a (a + v) ⊆ S
Instances For
A trivial example: the closed ball of radius 1 in ℝⁿ
is a Kakeya set.
The Kakeya set conjecture in dimension n
: the statement that every Kakeya set in ℝⁿ
has
Hausdorff dimension n
.
Equations
- Kakeya.KakeyaSetConjectureDim n = ∀ (S : Set (EuclideanSpace ℝ (Fin n))), Kakeya.IsKakeya S → dimH S = ↑n
Instances For
The two-dimensional case, proved by Davies [Da71].
[Da71] Davies, R. O., Some remarks on the Kakeya problem. Math. Proc. Cambridge Philos. Soc. 69 (1971), no. 3, 417–421.
The three-dimensional case, proved by Wang, Zahl [WaZa25].
[WaZa25] Wang, H. and Zahl, J., Volume estimates for unions of convex sets, and the Kakeya set conjecture in three dimensions. arXiv preprint, arXiv:2502.17655, 2025.
The finite field Kakeya conjecture asserts that any Kakeya set in 𝔽_qⁿ
has size at
least c_n · qⁿ
for some constant c_n
depending only on n
.
This was first proved by Dvir [Dv08]. The best known bound to date, due to Bukh and Chao [BuCh21],
establishes that any Kakeya set in 𝔽_qⁿ
has size at least qⁿ / (2 - 1/q)^(n - 1)
.
[Dv08] Dvir, Z., On the size of Kakeya sets in finite fields. Journal of the American Mathematical Society 22 (2009), no. 4, 1093–1097. [BuCh21] Bukh, B. and Chao, T.-W., Sharp density bounds on the finite field Kakeya problem. Discrete Analysis 26 (2021), 9 pp.