Artin's Conjecture on Primitive Roots, first half.
Let a be an integer that is not a square number and not −1. Then the set S(a)
of primes p
such that a
is a primitive root modulo p
has a positive asymptotic
density inside the set of primes. In particular, S(a)
is infinite.
Artin's Conjecture on Primitive Roots, second half.
Write a = a_0 b^2
where a_0
is squarefree. Under the conditions that a
is not a perfect power and a_0
is not congruent to 1
modulo 4
(sequence A085397 in the OEIS), the density of the set S(a)
of primes p
such that a
is a primitive root modulo p
is independent of a
and equals Artin's constant,
Artin's Conjecture on Primitive Roots, second half, different residue version
If a
is a square number or a = −1
, then the density of the set S(a)
of primes p
such that a
is a primitive root modulo p
is 0
.
Artin's Conjecture on Primitive Roots, second half, power version
If a
is a perfect pth power for prime p
, then the density of the set S(a)
of
primes p
such that a
is a primitive root modulo p
is given by p(p-2) / (p^2 - p - 1) * C
where C
is Artin's constant. If there are
more than one such prime p
, then the number needs to be multiplied by
``p(p-2) / (p^2 - p - 1)for all such primes
p`.
Artin's Conjecture on Primitive Roots, second half, perfect prime power version
Write a = a_0 b^2
where a_0
is squarefree.
If a_0
is congruent to 1 mod 4
, then the density of the set S(a)
of primes p
such that a
is a primitive root modulo p
is given by C * ∏_p, p(p-1) / (p^2 - p - 1)
where C
is Artin's constant and the product is taken over the prime factors p
of a_0