Erdős Problem 92 #
Reference: erdosproblems.com/92
For a given point x
and a set of other points, this function finds the maximum number of points
that lie on a single circle centered at x
. It does this by grouping the other points by their
distance to x
and finding the size of the largest group.
Equations
- One or more equations did not get rendered due to their size.
Instances For
This property holds for a set of points A
if every point x
in A
has at least k
other
points from A
that are equidistant from x
.
Equations
- Erdos92.hasMinEquidistantProperty k A = (A.Nonempty ∧ ∀ x ∈ A, k ≤ Erdos92.maxEquidistantPointsAt x A)
Instances For
The set of all possible values k
for which there exists a set of n
points
satisfying the hasMinEquidistantProperty k
. The function f(n)
will be the supremum of this set.
Equations
- Erdos92.possible_f_values n = {k : ℕ | ∃ (points : Finset (EuclideanSpace ℝ (Fin 2))) (_ : points.card = n), Erdos92.hasMinEquidistantProperty k points}
Instances For
A sanity check to ensure the set of possible f(n)
values is bounded above. A trivial bound is
n-1
, since any point can have at most n-1
other points equidistant from it.
This ensures sSup
is well-defined.