Erdős Problem 889 #
Reference: erdosproblems.com/889
$v(n,k)$ counts the prime factors of $n+k$ which do not divide $n+i$ for all $0 \le i < k$.
Equations
- Erdos889.v n k = {p ∈ (n + k).primeFactors | ∀ i ∈ Finset.range k, ¬p ∣ n + i}.card
Instances For
$v_0(n)$ is the supremum of $v(n,k)$ for all $k \ge 0$.
Equations
- Erdos889.v₀ n = ⨆ (k : ℕ), ↑(Erdos889.v n k)
Instances For
Let $v(n,k)$ count the prime factors of $n+k$ which do not divide $n+i$ for $0\leq i < k$. Is it true that $v_0(n)=\max_{k\geq 0}v(n,k)\to \infty$ as $n\to \infty$?
$v_l(n)$ is the supremum of $v(n,k)$ for all $k \ge l$
Equations
- Erdos889.v_l l n = ⨆ (k : ℕ), ⨆ (_ : k ≥ l), ↑(Erdos889.v n k)
Instances For
Let $v_l(n) = \max_{k\geq l} v(n,k)$. For every fixed $l$, $v_l(n) \to \infty$ as $n \to \infty$
[ErSe67] Erdős, P. and Selfridge, J. L., Some problems on the prime factors of consecutive integers. Illinois J. Math. (1967), 428--430.
$V(n,k)$ is the number of primes $p$ such that $p^\alpha$ exactly divides $n+k$ and for all $0 \le i < k$, $p^\alpha$ does not divide $n+i$, where $\alpha$ is the multiplicity of $p$ in the factorization of $n+k$.
Equations
- Erdos889.V n k = {p ∈ (n + k).primeFactors | ∀ i ∈ Finset.range k, ¬p ^ (n + k).factorization p ∣ n + i}.card
Instances For
$V_l(n)$ is the supremum of $V(n,k)$ for all $k \ge l$
Equations
- Erdos889.V_l l n = ⨆ (k : ℕ), ⨆ (_ : k ≥ l), ↑(Erdos889.V n k)
Instances For
Does $V_1(n) = 1$ have finite solutions?
This is a modification of erdos_889.variants.v1_eq_1_finite,
which might make it more amenable to attack according to [ErSe67].
[ErSe67] Erdős, P. and Selfridge, J. L., Some problems on the prime factors of consecutive integers. Illinois J. Math. (1967), 428--430.