Are there infinitely many pairs of integers $n < m$ such that $\binom{2n}{n}$ and $\binom{2m}{m}$ have the same set of prime divisors?
Show that for all $n$, the binomial coefficient $\binom{2n}{n}$ is even.
Are there infinitely many pairs of integers $n < m$ such that $\binom{2n}{n}$ and $\binom{2m}{m}$ have the same set of prime divisors?
Show that for all $n$, the binomial coefficient $\binom{2n}{n}$ is even.