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FormalConjectures.ErdosProblems.«678»

Erdős Problem 678 #

Reference: erdosproblems.com/678

def lcmInterval (n k : ) :

Write $M(n, k)$ be the least common multiple of ${n+1, \dotsc, n+k}$, denoted here as lcmInterval n k.

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    The referee of [Er79] found the example $M(96, 7) > M(104, 8)$, showing that there are cases where $M(n, k) > M(m, k + 1)$ with $m \geq n + k$. [Er79] Erdős, Paul, Some unconventional problems in number theory. Math. Mag. (1979), 67-70.

    The referee of [Er79] found the example $M(132, 7) > M(139, 8)$, showing that there are cases where $M(n, k) > M(m, k + 1)$ with $m \geq n + k$. [Er79] Erdős, Paul, Some unconventional problems in number theory. Math. Mag. (1979), 67-70.

    Cambie [Ca24] found the example $M(52, 7) > M(62, 8)$. [Ca24] S. Cambie, Resolution of an Erdős' problem on least common multiples. arXiv:2410.09138 (2024).

    Cambie [Ca24] found the example $M(36, 8) > M(48, 9)$. [Ca24] S. Cambie, Resolution of an Erdős' problem on least common multiples. arXiv:2410.09138 (2024).

    theorem erdos_678 :
    (∀ (k : ), 3 k{(m, n) : × | n + k m lcmInterval m (k + 1) < lcmInterval n k}.Infinite) True

    Write $M(n, k)$ be the least common multiple of ${n+1, \dotsc, n+k}$. Let $k \geq 3$. Are there infinitely many $m, n$ with $m \geq n + k$ such that $$ M(n, k) > M(m, k + 1) $$? The answer is yes, as proved in a strong form by Cambie [Ca24]. [Ca24] S. Cambie, Resolution of an Erdős' problem on least common multiples. arXiv:2410.09138 (2024).