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FormalConjectures.ErdosProblems.«358»

Erdős Problem 358 #

Reference: erdosproblems.com/358

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    noncomputable def Erdos358.f (A : ) (n : ) :
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        noncomputable def Erdos358.g (A : ) (n : ) :
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          theorem Erdos358.f_id :
          f id = fun (n : ) => (Finset.filter Odd n.divisors).card

          When $A_n = n$, the function $f$ defined above counts the number of odd divisors of $n$.

          Let $A=\{a_1 < \cdots\}$ be an infinite sequence of integers. Let $f(n)$ count the number of solutions to [n=\sum_{u\leq i\leq v}a_i.] Is there such an $A$ for which $f(n)\to \infty$ as $n\to \infty$?

          theorem Erdos358.erdos_358.parts.ii :
          (∃ (A : ), StrictMono A ∀ᶠ (n : ) in Filter.atTop, 2 f A n) sorry

          Let $A=\{a_1 < \cdots\}$ be an infinite sequence of integers. Let $f(n)$ count the number of solutions to [n=\sum_{u\leq i\leq v}a_i.] Is there an $A$ such that $f(n)\geq 2$ for all large $n$?

          When $A =\{a_1 < \cdots\}$ corresponds to the set of primes, it is conjectured that the $\limsup$ of the number of representations [n=\sum_{u\leq i\leq v}a_i] is infinite.

          When $A =\{a_1 < \cdots\}$ corresponds to the set of primes, it is conjectured that the set of numbers $n$ that have representations [n=\sum_{u\leq i\leq v}a_i] has positive upper density.

          It is conjectured that if $A =\{a_1 < \cdots\}$ and $g$ counts the number of representations [n=\sum_{u\leq i\leq v}a_i] such that the sum has at least two terms, then for all $n$ we have $1 \leq g(n)$ for sufficiently large $n$.